Consider the infinite 1D chain formed by placing boron atoms between the H 2 molecules from Problem

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Consider the infinite 1D chain formed by placing boron atoms between the H2 molecules from Problem 6.7 to form an infinite chain (shown below) where the B–H distance is 1.27 Å while B–B and H–H are both 1.8 Å. The calculated band structure for this chain is shown below.

(a) Which of the boron orbitals can mix (form bonding/antibonding crystal orbitals) with the H2 bonding orbital, ψ+, at k = 0? Which boron orbital can mix with ψ+ at k = π/a?

(b) Which of the boron orbitals can mix with the H2 antibonding orbital, ψ−, at k = 0? Which boron orbital can mix with ψ− at k = π/a?

(c) What is the AO character of the two crystal orbitals that become degenerate at k = π/a?

(d) At k = 0, only the lowest-energy band has both B–H and H–H σ-bonding character. What is the AO character of this band at k = 0?

(e) At k = 0, the highest-energy band (E = +33.8 eV) has both B–H and H–H σantibonding character. What orbitals contribute to this band at k = 0?

energy (eV) 36 24 12 -12 -24 0 E H H H  k H H 8 H H n/a

Problem 6.7

Consider an infinite 1D chain of H2 molecules where the molecular axis is oriented perpendicular to the chain direction, as shown below.

H +++  H I   H + H H I H ++ H I

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Related Book For  answer-question

Solid State Materials Chemistry

ISBN: 9780521873253

1st Edition

Authors: Patrick M. Woodward, Pavel Karen, John S. O. Evans, Thomas Vogt

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