Calculate the B-basis allowable strengths with 5, 10, 20, and 30 coupons, and show the calculated allowable

Question:

Calculate the B-basis allowable strengths with 5, 10, 20, and 30 coupons, and show the calculated allowable strengths converge to the true allowable strength in example 10.1. The coupon test results can be simulated by generating random numbers from a normal distribution with mean \(=310 \mathrm{MPa}\) and standard deviation = \(25 \mathrm{MPa}\). The true tenth percentile of the distribution is \(278 \mathrm{MPa}\). Plot a graph of the allowable strength versus the number of coupons, and show that the curve converges to \(278 \mathrm{MPa}\).

Data From Example 10.1:

Calculate the Bbasis allowable strength of aluminum alloy 6061T6 when the measured failure strengths of ten coupons are given as

\(\sigma=\{351.5,246.7,318.1,310.4,350.2,294.4,292.7,333.5,309.3,327.6\}\) МРа.

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Related Book For  answer-question

Introduction To Finite Element Analysis And Design

ISBN: 9781119078722

2nd Edition

Authors: Nam H. Kim, Bhavani V. Sankar, Ashok V. Kumar

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