The circuit of Figure P7=51 is a two-stage, firstorder cascade circuit that will be studied extensively in Chapter 14. It is a second-order circuit whose zero-state step response can be solved by recognizing that since $R$ and $C$ are the same, the solution fits Case B for the natural response $v_{2N}\left(t\right)$ ( Eq.7二 65b. ) Note both the similarity and the difference between the circuit in Figure P7-50 and Figure P7=51. As we will study later, the former is a band-pass filter, while the latter is a secondorder low-pass filter.

(a) For the circuit in Figure P7=51 find the output $v_2\left(t\right)$ when the input $v_S\left(t\right)=5u\left(t\right),R=10k\Omega$, and $C=0.1\mu F$.

(b) Use MATLAB to plot your result.
(c) Simulate together both the filter in Figure P7=50 and that in Figure P7=51 using Multisim. Note that both filters have similar component values and input step functions. What conclusions can you draw about the step responses of these circuits?

Transcribed Image Text:

YN (t)=Ke + Kte-at t20