7. Disassemble the following instructions. There is a continuation page if you need more space. Here...
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7. Disassemble the following instructions. There is a continuation page if you need more space. Here is an example for the hex machine code value 0x8FA3001C. Expanding the leftmost 6 bits (the Ox8 and left two bits of OxF) yields 100011. This is non-zero so it's not R-type and does not have the value 000010 (1) or 000011 (jal), so it must be an I-type instruction. Therefore, we can dehexify into the I-type field format. Ox8FA3001C (left 6100011): 1-type: 26:25 21:20 16:15 31 opcode 8 1000 11 lw TS F 3 0 C 00011 0000 0000 0001 1100 0x001C Sv1 0x8FA3001C1v Svi, 28($sp) or lw $vi, oxiC($sp) Again, the 35 block grid will accomodate a 32 bit entity. (a) (5 pts) 0x2009000A A 11/101 Ssp (b) (5 pts.) 0x912B0000 rt (c) (5 pts) 0x02355825 address/immediate 0 0: ← field names hex values + debexify into fields -convert hex to assembly language tokens assembly language statement 7. Disassemble the following instructions. There is a continuation page if you need more space. Here is an example for the hex machine code value 0x8FA3001C. Expanding the leftmost 6 bits (the Ox8 and left two bits of OxF) yields 100011. This is non-zero so it's not R-type and does not have the value 000010 (1) or 000011 (jal), so it must be an I-type instruction. Therefore, we can dehexify into the I-type field format. Ox8FA3001C (left 6100011): 1-type: 26:25 21:20 16:15 31 opcode 8 1000 11 lw TS F 3 0 C 00011 0000 0000 0001 1100 0x001C Sv1 0x8FA3001C1 $v1, 28($sp) or lv Svi, OxiC($sp) Again, the 35 block grid will accomodate a 32 bit entity. (a) (5 pts) 0x2009000A A 11/101 Ssp (b) (5 pts) 0x912B0000 rt (c) (5 pts) 0x02355825 address/immediate 0 0: ← field names hex values + debexify into fields -convert hex to assembly language tokens assembly language statement 7. Disassemble the following instructions. There is a continuation page if you need more space. Here is an example for the hex machine code value 0x8FA3001C. Expanding the leftmost 6 bits (the Ox8 and left two bits of OxF) yields 100011. This is non-zero so it's not R-type and does not have the value 000010 (1) or 000011 (jal), so it must be an I-type instruction. Therefore, we can dehexify into the I-type field format. Ox8FA3001C (left 6100011): 1-type: 26:25 21:20 16:15 31 opcode 8 1000 11 lw TS F 3 0 C 00011 0000 0000 0001 1100 0x001C Sv1 0x8FA3001C1v Svi, 28($sp) or lw $vi, oxiC($sp) Again, the 35 block grid will accomodate a 32 bit entity. (a) (5 pts) 0x2009000A A 11/101 Ssp (b) (5 pts.) 0x912B0000 rt (c) (5 pts) 0x02355825 address/immediate 0 0: ← field names hex values + debexify into fields -convert hex to assembly language tokens assembly language statement 7. Disassemble the following instructions. There is a continuation page if you need more space. Here is an example for the hex machine code value 0x8FA3001C. Expanding the leftmost 6 bits (the Ox8 and left two bits of OxF) yields 100011. This is non-zero so it's not R-type and does not have the value 000010 (1) or 000011 (jal), so it must be an I-type instruction. Therefore, we can dehexify into the I-type field format. Ox8FA3001C (left 6100011): 1-type: 26:25 21:20 16:15 31 opcode 8 1000 11 lw TS F 3 0 C 00011 0000 0000 0001 1100 0x001C Sv1 0x8FA3001C1 $v1, 28($sp) or lv Svi, OxiC($sp) Again, the 35 block grid will accomodate a 32 bit entity. (a) (5 pts) 0x2009000A A 11/101 Ssp (b) (5 pts) 0x912B0000 rt (c) (5 pts) 0x02355825 address/immediate 0 0: ← field names hex values + debexify into fields -convert hex to assembly language tokens assembly language statement
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a Disassembling the instruction Ox2009000A Expanding the leftmost 6 bits Ox2 yields 001000 which cor... View the full answer
Related Book For
Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
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