DSB-SC requires more complex detection circuitry than amplitude modulation. In the below figure, the AD633 on...
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DSB-SC requires more complex detection circuitry than amplitude modulation. In the below figure, the AD633 on the left is being used to generate the DSB-SC modulated signal. The blue line represents the transmitted radio wave. The AD633 on the right is the receiver. carrier x1 OV Baseband signal Y1 3 10V OV AD633JN/AD633AN W = (x1-x2)(Y1-Y2) + Z 10V Transmitter power 8 +Vs 7 W 6 Z X1 1 OV Y1 5-VS power OV 10V A AD633JN/AD633AN (X1-x2)(Y1-Y2)+z 10V Receiver W = +Vs power W Z Baseband signal -Vs power In the real world, the receiver would be located far away from the transmitter. It would need to have its own local oscillator to achieve demodulation, by multiplying the received signal by the carrier frequency. In the demodulation laboratory or simulation, we had complete control over the local oscillator. Whether the experiments were performed using lab equipment or in simulation, there was a known and fixed phase difference between the carrier signal and the local oscillator. Which of these statements are true? Select all correct statements. Selecting incorrect statements will subtract marks for this question. The phase of the local oscillator could be ensured using a phase-locked-loop The local oscillator should be in phase with the modulation carrier to ensure that the amplitude of the received baseband signal is as large as possible The signal applied to pin Y1 of the receiver should be a local oscillator at the carrier frequency The envelope detector would be just as good at demodulating the DSB-SC signal as the method shown here The phase of the local oscillator is not important for demodulation of the signal The signal applied to pin Y1 of the receiver should be a local oscillator at the baseband message frequency DSB-SC requires more complex detection circuitry than amplitude modulation. In the below figure, the AD633 on the left is being used to generate the DSB-SC modulated signal. The blue line represents the transmitted radio wave. The AD633 on the right is the receiver. carrier x1 OV Baseband signal Y1 3 10V OV AD633JN/AD633AN W = (x1-x2)(Y1-Y2) + Z 10V Transmitter power 8 +Vs 7 W 6 Z X1 1 OV Y1 5-VS power OV 10V A AD633JN/AD633AN (X1-x2)(Y1-Y2)+z 10V Receiver W = +Vs power W Z Baseband signal -Vs power In the real world, the receiver would be located far away from the transmitter. It would need to have its own local oscillator to achieve demodulation, by multiplying the received signal by the carrier frequency. In the demodulation laboratory or simulation, we had complete control over the local oscillator. Whether the experiments were performed using lab equipment or in simulation, there was a known and fixed phase difference between the carrier signal and the local oscillator. Which of these statements are true? Select all correct statements. Selecting incorrect statements will subtract marks for this question. The phase of the local oscillator could be ensured using a phase-locked-loop The local oscillator should be in phase with the modulation carrier to ensure that the amplitude of the received baseband signal is as large as possible The signal applied to pin Y1 of the receiver should be a local oscillator at the carrier frequency The envelope detector would be just as good at demodulating the DSB-SC signal as the method shown here The phase of the local oscillator is not important for demodulation of the signal The signal applied to pin Y1 of the receiver should be a local oscillator at the baseband message frequency
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Solution The correct statements are The local oscillator should be in phase with the modulation carrier to ensure that the amplitude of the received b... View the full answer
Related Book For
Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
Posted Date:
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