s 22 and 23. Show full solution and final answer. Thanks!

Question 22 (3 points) What will be the [Hgot]] if 0.001500 moles of HCI is added to 2.000 L of water ? The reaction gives the conversion factor HCI + H,O - Hoot! + ci-1 start: 0.00150 0 0 equil: note: this is related to the next problem 0.00300 M 0.150 M 0.000015 M 0.000150 M 0.00150 M 0.00075 M Question 23 (3 points) PH = - log [H30-1] [H30+1] = 10-TH POH - - log [OH 1 ] [OH-1] = 10-POH PH + POH = 14 [H30+1][OH-1] = 10-14 What will be the pH if 0.00150 moles of HCI is added to 2.000 L of water ? The reaction gives the conversion factor HCI + H20 - Haof] + ci-1 start: 0.00150 O O equil: 0 3.125 2.5223 6.502 2.824 1.412 1.5000