Question: A box contains 4 right-handed and 6 left-handed screws, two screws are drawn at random without replacement. Let X be the number of left-handed screws

A box contains 4 right-handed and 6 left-handed screws, two screws are drawn at random without replacement. Let X be the number of left-handed screws drawn. Find the probabilities P(X = 0), P(X = 1), P(X = 2), P(1 < X < 2), P(X < 1), P(X > 1), P(X > 1), and P(0.5< X < 10).

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