Question: A differentiable functional f on an open set S n is quasiconcave if and only if Inequality (36) can be strengthened where f is regular.
Inequality (36) can be strengthened where f is regular.
f(x) f(xo)Vf(xo)x xo) 2 for every x, xo in S (36)
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Assume is quasiconcave and x x 0 Differentiability at x 0 implies for all 0 1 x 0 x x 0 x 0 x 0 x x ... View full answer
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