A forced damped spring-mass system (Figure) has the following ordinary differential equation of motion: Where x =

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A forced damped spring-mass system (Figure) has the following ordinary differential equation of motion:


dx dx +a dt di dr? + kx = F, sin(wr)


Where x = displacement from the equilibrium position, t = time, m = 2 kg mass, α = 5 N/(m/s)2, and k 6 N/(m/s)2. The damping term is nonlinear and represents air damping. The forcing function Fα sin (ωt)has values of Fα = 2.5 N and ω = 0.5 rad/sec. The initial conditions are

Initial velocity             dx/dt = 0 m/s

Initial displacement     x = I m



A forced damped spring-mass system (Figure) has the following or


Solve this equation using a numerical method over the time period 0 ≤ t ≤ 15 s. Plot the displacement and velocity versus time, and plot the forcing function on the same curve. Also, develop a separate plot of velocity versus displacement.

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Numerical Methods For Engineers

ISBN: 9780071244299

5th Edition

Authors: Steven C. Chapra, Raymond P. Canale

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