Question: A galvanic cell is based on the following half reactions: Cu 2+ + 2e - Cu(s) o = 0.34 V V 2+ +
A galvanic cell is based on the following half reactions:
Cu2+ + 2e- → Cu(s) ϐo = 0.34 V
V2+ + 2e- → V(s) ϐo = 21.20 V
In this cell the copper compartment contains a copper electrode and [Cu2+] = 1.00 M, and the vanadium compartment contains a vanadium electrode and V2+ at an unknown concentration. The compartment containing the vanadium (1.00 L of solution) was titrated with 0.0800 M H2EDTA2-, resulting in the reaction
H2EDTA2-(aq) + V2+(aq) ⇌ VEDTA2-(aq) + 2H+(aq) K = ? The potential of the cell was monitored to determine the stoichiometric point for the process, which occurred at a volume of 500.0 mL of H2EDTA2- solution added. At the stoichiometric point, ϐ cell was observed to be 1.98 V. The solution was buffered at a pH of 10.00.
a. Calculate ϐ cell before the titration was carried out.
b. Calculate the value of the equilibrium constant K for the titration reaction.
c. Calculate ϐ cell at the halfway point in the titration.
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a To determine E cell we must know the initial V 2 which can be determined from the stoichiometric p... View full answer
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