Question: A Geiger-Marsden experiment, in which alpha particles are scattered off a thin gold film, yields an intensity of I(95.1) = 1129 counts/s at a scattering

A Geiger-Marsden experiment, in which alpha particles are scattered off a thin gold film, yields an intensity of I(95.1°) = 1129 counts/s at a scattering angle of 95.1° ± 0.4°. At a second scattering angle, the intensity is measured to be 4840 counts/s. Assuming that the scattering obeys the Rutherford formula, what is that second angle (in degrees, to the same uncertainty)?

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