Question: (a) Given an arbitrary set of numbers {Mαβ ; α = 0, . . . , 3; β = 0, . . . , 3}

(a) Given an arbitrary set of numbers {Mαβ ; α = 0, . . . , 3; β = 0, . . . , 3} and two arbitrary sets of vector components {Aμ,μ = 0, . . . , 3} and {Bν , ν = 0, . . . , 3}, show that the two expressions
(a) Given an arbitrary set of numbers {Mαβ ; α

And

(a) Given an arbitrary set of numbers {Mαβ ; α

Are not equivalent.
(b) Show that
AαBβηαβ = ˆ’A0B0 + A1B1 + A2B2 + A3B3.

MaBA B

Step by Step Solution

3.32 Rating (161 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a The double sum is obviously differ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

953-P-M-P-R (839).docx

120 KBs Word File

Students Have Also Explored These Related Modern Physics Questions!