Question: (a) If m is a particle's mass, p is its momentum magnitude, and K is its kinetic energy, show that m = (pc)2 K2/2kc2.

(a) If m is a particle's mass, p is its momentum magnitude, and K is its kinetic energy, show that m = (pc)2 – K2/2kc2.

(b) For low particle speeds, show that the right side of the equation reduces to m.

(c) If a particle has K = 55.0MeV when p = 121MeV/c, what is the ratio m/me of its mass to the electron mass?

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a Squaring Eq 3747 gives which we set equal to Eq 3755 Thus E mc 2mc K K mc 2mcK K pc mc m c H... View full answer

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