Question: (a) If the base of the radiator is maintained at Tb = 80C, what is its tip temperature and the rate of heat rejection? Use

(a) If the base of the radiator is maintained at Tb = 80°C, what is its tip temperature and the rate of heat rejection? Use a computer-based, finite-difference method with a space increment of 0.1 m to obtain your solution.

(b) Repeat the calculation of part (a) for the case when the space ship is on the dark side of the earth and is not exposed to the sun.

(c) Use your computer code to calculate the heat rate and tip temperature for G s = 0 and an extremely large value of the thermal conductivity. Compare your results to those obtained from a hand calculation that assumes the radiator to be at a uniform temperature Tb, what other approach might you use to validate your code?

G,- 1353 Wim? 1= 12 mm T, = 80C W -6 m

G,- 1353 Wim? 1= 12 mm T, = 80C W -6 m L=1 m

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