Question: A mixture is 10.0mole % ethyl alcohol 75.0 mole% ethyl acetate (C 4 H 8 O 2 ) and 15.0mole% acetic acid. Calculate the mass

A mixture is 10.0mole % ethyl alcohol 75.0 mole% ethyl acetate (C₄H₈O₂) and 15.0mole% acetic acid. Calculate the mass fractions of each compound. What is the average molecular weight of the mixture? What would be the mass (kg) of a sample containing 25.0kmol of ethyl acetate?

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Assume 100 mol mix mcHOH mcHO MCHCOOH XCHOH 461 g 461 g 6608 g 901 g 6608 g 461 g 6608 g 90... View full answer

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