Question: A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity p. You want to change the applied potential

A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity p. You want to change the applied potential difference and stretch the wire so that the energy dissipation rate is multiplied by 30.0 and the current is multiplied by 4.00. Assuming the wire's density does not charge, what are

(a) The ratio of the new length to L and

(b) The ratio of the new cross-sectional area to A?

Step by Step Solution

3.47 Rating (163 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

We use P R pLA or LA Pip a The new values of L and ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

2-P-M-C-R (247).docx

120 KBs Word File

Students Have Also Explored These Related Electricity and Magnetism Questions!