A proton with a kinetic energy of 4.6 10-16 J moves perpendicular to a magnetic field

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A proton with a kinetic energy of 4.6 × 10-16 J moves perpendicular to a magnetic field of 0.36 T. What is the radius of its circular path?

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Physics

ISBN: 978-0321976444

5th edition

Authors: James S. Walker

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Question Posted: Aug 31, 2017 12:07 PM

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A proton with a kinetic energy of 4.6 10-16 J moves perpendicular to a magnetic field

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