Question: A sample of S8(g) is placed in an otherwise empty, rigid container at 1325 K at an initial pressure of 1.00 atm, where it decomposes

A sample of S8(g) is placed in an otherwise empty, rigid container at 1325 K at an initial pressure of 1.00 atm, where it decomposes to S2(g) by the reaction S8(g) ⇌ 4S2(g) At equilibrium, the partial pressure of S8 is 0.25 atm. Calculate Kp for this reaction at 1325 K.

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S 8 g 4 S 2 g K p Initially 100 atm and 0 atm Change Because 025 atm of S 8 remain at equilibrium 1... View full answer

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