Question: A slender rod, 0.240 m long, rotates with an angular speed of 8.80 rad/s about an axis through one end and perpendicular to the rod.

A slender rod, 0.240 m long, rotates with an angular speed of 8.80 rad/s about an axis through one end and perpendicular to the rod. The plane of rotation of the rod is perpendicular to a uniform magnetic field with a magnitude of 0.650 T.
(a) What is the induced emf in the rod?
(b) What is the potential difference between its ends?
(c) Suppose instead the rod rotates at 8.80 rad/s about an axis through its center and perpendicular to the rod. In this case, what is the potential difference between the ends of the rod, between the center of the rod and one end?

Step by Step Solution

3.45 Rating (177 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a IDENTIFY Use the expression for motional emf to calculate the emf induced in the rod SET UP The ro... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

P-E-E-I (233).docx

120 KBs Word File

Students Have Also Explored These Related Electricity and Magnetism Questions!