Question: A vertical spring (spring constant = 112 N/m) is mounted on the floor. A 0.400-kg block is placed on top of the spring and pushed

A vertical spring (spring constant = 112 N/m) is mounted on the floor. A 0.400-kg block is placed on top of the spring and pushed down to start it oscillating in simple harmonic motion. The block is not attached to the spring.
(a) Obtain the frequency (in Hz) of the motion.
(b) Determine the amplitude at which the block will lose contact with the spring.

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REASONING a The angular frequency in rads is given by Equation 1011 k where k is the spring const... View full answer

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