Question: A voltaic cell is constructed that uses the following half-cell reactions: The cell is operated at 298 K with [Cu+] = 0.20 M and [I-]
The cell is operated at 298 K with [Cu+] = 0.20 M and [I-] = 3.5 M.
(a) Determine E for the cell at these concentrations.
(b) Which electrode is the anode of the cell?
(c) Is the answer to part (b) the same as it would be if the cell were operated under standard conditions?
(d) If [Cu+] was equal to 0.15 M, at what concentration of would I- the cell have zero potential?
Cu+ (aq) + e- Cu(s) 12 (s) + 2 e'-> 21-(aq)
Step by Step Solution
3.52 Rating (155 Votes )
There are 3 Steps involved in it
a b Since the cell potential is positive at these concentration conditions the reaction as written ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
876-E-C-E-E-C (1117).docx
120 KBs Word File
