Question: According to Eq. 4.5, the force on a single dipole is (p ?? ??)E, so the net force on a dielectric object is [Here Eext

According to Eq. 4.5, the force on a single dipole is (p ?? ??)E, so the net force on a dielectric object is [Here Eext is the field of everything except the dielectric. You might assume that it wouldn't matter if you used the total field; after all, the dielectric can't exert a force on itself. However, because the field of the dielectric is discontinuous at the location of any bound surface charge, the derivative introduces a spurious delta function, and you must either add a compensating surface term, or (better) stick with Eext, which suffers no such discontinuity.] Use Eq. 4.69 to determine the force on a tiny sphere of radius R, composed of linear dielectric material of susceptibility Xe, which is situated a distance s from a fine wire carrying a uniform line charge λ.

F = [(P. V)Eext dt. (4.69)

F = [(P. V)Eext dt. (4.69)

Step by Step Solution

3.38 Rating (182 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

X Eext Since the sphere is tiny this is ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

5-P-E-E-F (37).docx

120 KBs Word File

Students Have Also Explored These Related Electrodynamics Questions!