Acetaldehyde, CH3CHO, decomposes when heated. CH3CHO(g) CH4(g)Ã CO(g) The rate constant for the decomposition is 1.05Ã 103/(M1/2s)
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CH3CHO(g) †’ CH4(g)× CO(g)
The rate constant for the decomposition is 1.05× 103/(M1/2ˆ™s) at 759 K and 2.14 ×
102/(M1/2ˆ™s) at 836 K. What is the activation energy for this decomposition? What is the
rate constant at 865 K?
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Solve for Ea by substituting the given values into the twotemperat...View the full answer
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