Calculate the volume of 0.0500 M EDTA needed to titrate (a) 29.13 mL of 0.0598 M Mg(NO3)2.
Question:
(a) 29.13 mL of 0.0598 M Mg(NO3)2.
(b) The Ca in a 0.4861-g mineral specimen that is 81.4% brushite, CaHPO4·2H2O (172.09 g/mol).
(c) The Ca and Mg in a 0.1612-g sample that is 92.5% dolomite, CaCO3·MgCO3 (184.4 g/mol).
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a b c Vol EDTA 00598 ...View the full answer
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Related Book For 
Fundamentals of Analytical Chemistry
ISBN: 978-0495558286
9th edition
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
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