Question: Capacitors in networks cannot always be grouped into simple series or parallel combinations. As an example, Fig .a shows three capacitors Cx, Cy, and Cz
(a) Show that the transformation equations that give C1, C2, and C3 in terms of Cx, and CY, and Cz are
(b) For the network shown in Fig.c, determine the equivalent capacitance between the terminals at the left end of the network.
(c) Determine the charges of, and the potential differences across, each capacitor in Fig c.
(a) C = (C,C, + C,C, + CC.)/C, C = (C,C, + C,C, + CC.)C, C, = (C,C, + C,C, + C,C,)/C, %3D V, (b) be (c) 72.0 pF 27.0 uF 18.0 6.0 F 36,0V 28.0 21.0 pF 72.0 F
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IDENTIFY and SET UP Show the transformation from one circuit to the other 93 C 93 is derived from Vab Vab 93 93 C 1 and C C 27 F 6 F Circuit 1 EXECUTE ... View full answer
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