Question: Consider a digital communication system that uses a repetition code for the channel encoding/decoding. In particular, each transmission is repeated times, where n = 2m
Consider a digital communication system that uses a repetition code for the channel encoding/decoding. In particular, each transmission is repeated times, where n = 2m + 1 is an odd integer. The decoder operates as follows, if in a block of n received hits, the number of 0s exceeds the number of is, the decoder decides in favor of a 0. Otherwise, it decides in favor of a 1. An error occurs when m + 1 or more transmissions out of n = 2m + 1 are incorrect. Assume a binary symmetric channel.
(a) For n = 3, show that the average probability of error is given by Pe = 3p2(l ? p) + p3?where p is the transition probability of the channel.
(b) For is 5, show that the average probability of error is given by Pe = 10p3?(1 ? p)2 + 5p4(1 ? p) + p5
(c) Hence, for the general case, deduce that the average probability of error is given by

P. = p'(1-p"-i
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a When each symbol is repeated three times we have Messages 000 1 2 111 Unused signals 001 010 011 1... View full answer
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