Consider a rigid slab initially at rest and subjected to an impulsive force F contained in the plane of the slab. We define the center of percussion P as the point of intersection of the line of action of F with the perpendicular drawn from G.

(a) Show that the instantaneous center of rotation C of the slab is located on line GP at a distance GC = k2/GP on the opposite side of G.

(b) Show that if the center of percussion were located at C the instantaneous center of rotation would be located at P.

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