Question: Consider an N-point sequence x[n] with DFT X[k], k = 0, 1, ?, N ? 1. The following algorithm computes the even-indexed DFT values X[k],
Consider an N-point sequence x[n] with DFT X[k], k = 0, 1, ?, N ? 1. The following algorithm computes the even-indexed DFT values X[k], k0, 2, ?. , N ? 2, for N even, using only a single N/2 ?point DFT:
1. Form the sequence y [n] by time aliasing, i.e.,
2. Compute Y [r], r = 0, 1, ?., (N/2) ? 1, the N/2-point DFT of y [n].
3. Then the even-indexed values of X[k] are X[k] = Y[k/2], for k = 0, 2, ?, N ? 2.
(a) Show that the preceding algorithm produces the desired results.
(b) Now suppose that we form a finite-length sequence y[n] from a sequence x[n] by, determine the relationship between the M-point DFT Y [k] and X (e j?), the Fourier transform of x[n]. Show that the result of part (z) is a special case of the result of part (b).
(c) Develop an algorithm similar to the one in part (a) to compute the odd-indexed DFT values X[k], k = 1, 3, ?, N ? 1, for N even, using only a single N/2-point DFT.?
![Part 1 x[n] + x[n + N/2]. 0](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2022/11/636a507e1fcba_806636a507e0fc1b.jpg)
Part 1 x[n] + x[n + N/2]. 0
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