Question: Consider Example 9.6 with the null hypothesis H0: P = P0 = 0.50 and the alternative hypothesis H0: P 0.50 The decision rule is

Consider Example 9.6 with the null hypothesis
H0: P = P0 = 0.50
and the alternative hypothesis
H0: P ‰ 0.50
The decision rule is

with a sample size of n = 600. What is the probability of Type II error if the actual population proportion is each of the following?
a. P = 0.52
b. P = 0.58
c. P = 0.53
d. P = 0.48
e. P = 0.43

0.50 Vo.50(1-0.50)/6001.95 or Pr 0.50 VO.50(1 050)/600 1.96

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