Question: Consider the circuit shown in the figure. The currents I1, I2, and I3 (in amperes) are the solution of the system where E1 and E2

Consider the circuit shown in the figure. The currents I1, I2, and I3 (in amperes) are the solution of the system

+ 41, = E, (21, 1 + 41, = E, I, + 12 - 1, = 0 %3D

where E1 and E2 are voltages. Use the inverse of the coefficient matrix of this system to find the unknown currents for the given voltages.

α 12 2Ω 1Ω 412 Ερ
+ 41, = E, (21, 1 + 41, = E, I, +

1. E1 = 15 volts, E2 = 17 volts
2. E1 = 10 volts, E2 = 10 volts

+ 41, = E, (21, 1 + 41, = E, I, + 12 - 1, = 0 %3D 12 2 1 412

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