Question: Consider the following linear programming problem: Max 3A + 3B s.t. 2A + 4B 12 6A + 4B 24 A, B 0
Max 3A + 3B
s.t.
2A + 4B ≤ 12
6A + 4B ≤ 24
A, B ≥ 0
a. Find the optimal solution using the graphical solution procedure.
b. If the objective function is changed to 2A + 6B, what will the optimal solution be?
c. How many extreme points are there? What are the values of A and B at each extreme point?
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a b c There are four extreme po... View full answer
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