Question: Consider the Minitab output below. (a) Fill in the missing values. (b) Can the null hypothesis be rejected at the 0.05 level? Why? (c) Use

Consider the Minitab output below.
Consider the Minitab output below. (a) Fill in the missing values.

(a) Fill in the missing values.
(b) Can the null hypothesis be rejected at the 0.05 level? Why?
(c) Use the output and the t-table to find a 99% CI on the difference in means.
(d) Suppose that the alternative hypothesis was H1: 1 = 2 versus H1: 1 > 2. What is the P-value? What conclusions would you draw?

Two-Sample T-Test and CI Sauple N Mea StDev SE Mean 0.45 0.56 1.75 15 50.20 15 51.99 2.15 Difference= mu (1)-mu (2) Estimate for difference: ? 95% CI ror a1rrerence: (-3.246, -0.314) T-Test of difference 0 [vs not=) T-Value-_2.49 D-Value = 0.019 DF Both use Pooled StDev1.9602 ?

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