Question: Consider the solid (Figure 9) in the first octant cut off from the square cylinder with sides x = 0, x = 1, y =
(a) Hard way: by a dr dz dy integration
(b) Easier way: by a dz dy dx integration
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x + y +z=4 y = 1 I = 1
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a It will be helpful to first label the corner points at th... View full answer
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