Question: Consider the space ((, A) and let A be as in Exercise 8. Define AA by AA = {B ( (; B = A (

Consider the space ((, A) and let A be as in Exercise 8. Define AA by AA = {B ( (; B = A ( C, C ( A}. Then AA is a σ-field (of subsets of A). Further-more, AA = σ(FA), where FA is as in Exercise 8 and A = σ(F).

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That A A and that it is closed under complementation is as in Exercise 8 For B i A A i 1 2 it follow... View full answer

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