Question: Consider two carboxylic acids (acids that contain the -COOH group): CH3COOH (acetic acid, Ka = 1.8 10-5) and CH2ClCOOH (chloroacetic acid, Ka = 1.4
Consider two carboxylic acids (acids that contain the -COOH group): CH3COOH (acetic acid, Ka = 1.8 × 10-5) and CH2ClCOOH (chloroacetic acid, Ka = 1.4 × 10 -3). (a) Calculate ×G° for the ionization of these acids at 25°C. (b) From the equation ×G° 5 ˆ†H° 2 Tˆ†S°, we see that the contributions to the ˆ†G° term are an enthalpy term (ˆ†H°) and a temperature times entropy term (Tˆ†S°). These contributions are listed below for the two acids:
.png)
Which is the dominant term in determining the value of ˆ†G° (and hence Ka of the acid)? (c) What processes contribute to ˆ†H°? (Consider the ionization of the acids as a Bronsted acid-base reaction.) (d) Explain why the TDS° term is more negative for CH3COOH.
A19 kJ/mol) -0.57 -4.7 TAS1J/mol) CH,COOH CH CICOOH 27.6 21.1
Step by Step Solution
3.29 Rating (173 Votes )
There are 3 Steps involved in it
a G for CH 3 COOH G 8314 Jmol K298 K ln 18 10 5 G 27 10 4 Jmol 27 kJmol G for CH 2 ClCOOH ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
932-C-O-C (2780).docx
120 KBs Word File
