Question: Consider two current loops (as in Fig) whose orientation in space is fixed, but whose relative separation can be changed. Let O 1 and O

Consider two current loops (as in Fig) whose orientation in space is fixed, but whose relative separation can be changed. Let O1 and O2 be origins in the two loops, fixed relative to each loop, and x1 and x2 be coordinates of elements dI1 and dI2, respectively, of the loops referred to the respective origins. Let R be the relative coordinate of the origins, directed from loop 2 to loop 1.

(a) Starting from (5.10), the expression for the force between the loops, show that it can be written


F12 = I1I2ÑRM12(R)


Where M12 is the mutual inductance of the loops,

dl, • dlz X1 - X2 + R| %3D M12(R)


And it is assumed that the orientation of the loops does not change with R.

(b) Show that the mutual inductance, viewed as a function of R, is a solution of the Laplace equation,

dl, dlz X1 - X2 + R| %3D M12(R)


The importance of this result is that the uniqueness of solutions of the Laplace equation allows the exploitation of the properties of such solutions, provided a solution can be found for a particular value of R.


dl, dlz X1 - X2 + R| %3D M12(R)

Step by Step Solution

3.38 Rating (170 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a We know that From the geome... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

44-P-M-F-L (128).docx

120 KBs Word File

Students Have Also Explored These Related Electricity and Magnetism Questions!