Question: Continuation of Problems 8 and 37. Another explanation is that the stones move only when the water dumped on the playa during a storm freezes
Continuation of Problems 8 and 37. Another explanation is that the stones move only when the water dumped on the playa during a storm freezes into a large, thin sheet of ice. The stones are trapped in place in the ice. Then, as air flows across the ice during a wind, the air-drag forces on the ice and stones move them both, with the stones gouging out the trails. The magnitude of the air-drag force on this horizontal "ice sail" is given by Dice = 4Cice(Aicev2, where Cice is the drag coefficient (2.0 ( 10-3), r is the air density (1.21 kg/m3), Aice is the horizontal area of the ice, and v is the wind speed along the ice.
Assume the following: The ice sheet measures 400 m by 500 m by 4.0 mm and has a coefficient of kinetic friction of 0.10 with the ground and a density of 917 kg/m3. Also assume that 100 stones identical to the one in Problem 8 are trapped in the ice. To maintain the motion of the sheet, what are the required wind speeds (a) near the sheet and (b) at a height of 10 m? (c) Are these reasonable values for high-speed winds in a storm?
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The layer of ice has a mass of m ice 917 kgm 3 400 m 500 m 00040 ... View full answer
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