Question: Deduce the structure of each of the following compounds on the basis of their 1H NMR spectra and molecular formulas: (a) C8H10; 1.2 ppm (triplet,

Deduce the structure of each of the following compounds on the basis of their 1H NMR spectra and molecular formulas:
(a) C8H10; δ 1.2 ppm (triplet, 3H)
δ 2.6 ppm (quartet, 2H)
δ 7.1 ppm (broad singlet, 5H)
(b) C10H14;
δ 1.3 ppm (singlet, 9H)
δ 7.0 to 7.5 ppm (multiplet, 5H)
(c) C6H14;
δ 0.8 ppm (doublet, 12H)
(f) C4H6Cl2; 2.2 ppm
(singlet, 3H)
δ 1.4 ppm (heptet, 2H)
δ 4.1 ppm (doublet,
2H)
(d) C6H12;
δ 0.9 ppm (triplet, 3H)
δ 5.7 ppm (triplet,
1H)
δ 1.6 ppm (singlet, 3H)
(g) C3H7ClO; δ 2.0 ppm
(pentet, 2H) δ 1.7 ppm (singlet, 3H)
δ 2.8 ppm (singlet,
1H) δ 2.0 ppm (pentet, 2H)
δ 3.7 ppm (triplet, 2H)
δ 5.1 ppm (triplet, 1H)
δ 3.8 ppm (triplet,
2H)
(e) C4H6Cl4;
δ 3.9 ppm (doublet, 4H)
(h) C14H14; δ 2.9 ppm
(singlet, 4H)
δ 4.6 ppm (triplet, 2H)
δ 7.1 ppm (broad
singlet, 10H)

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a A 5proton signal at 8 71 ppm indicates a monosubstituted aromatic ring With an index of hydrogen deficiency of 4 C8Ho contains this monosubstituted aromatic ring and no other rings or multiple bonds ... View full answer

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