Question: Define the sequence (cn) and (sn) inductively by c1(x) := 1, s1(x):= x, and for all n N, x R. Reason as in the proof
for all n N, x R. Reason as in the proof of Theorem 8.4.1 to conclude that there exist functions c : R R and s : R R such that (j) cʹʹ(x) = c(x) and sʹʹ(x) = s(x) for all x R, and (jj) c(0) = 1, cʹ(0) = 0 and s(0) = 0, sʹ(0) = 1. Moreover, cʹ(x) = s(x) and sʹ(x) = c(x) for all x R.
Cn(l)dt, C+1 0
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Clearly S n 0 0 and c n 0 1 also s n x c n x and c n1 x S n x for x R n N Show tha... View full answer
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