Question: Differentiating with respect to the expressions on both sides of the equation Show that the mean of the geometric distribution is given by

Differentiating with respect to θ the expressions on both sides of the equation

0a-or-1-1

Show that the mean of the geometric distribution is given by µ = 1/θ. Then, differentiating again with respect to θ, show that µ'₂ = 2 – θ / θ² and hence that σ² = 1 – θ / θ².

0a-or-1-1

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