Element X forms both a dichloride (XCl2) and a tetra-chloride (XCl4). Treatment of 10.00 g of XCl2
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Element X forms both a dichloride (XCl2) and a tetra-chloride (XCl4). Treatment of 10.00 g of XCl2 with excess chlorine forms 12.55 g of XCl4. Calculate the atomic weight (mass) of X and identify X.
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1000 g XCl 2 excess Cl 2 1255 g XCl 4 255 g Cl reacted with XCl 2 to form XCl 4 XCl 4 ...View the full answer
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