Question: Example 6.14 gave the probability distributions shown below for x = number of flaws in a randomly selected glass panel from Supplier 1 y =

Example 6.14 gave the probability distributions shown below for x = number of flaws in a randomly selected glass panel from Supplier 1 y = number of flaws in a randomly selected glass panel from Supplier 2 for two suppliers of glass used in the manufacture of flat screen TVs. If the manufacturer wanted to select a single supplier for glass panels, which of these two suppliers would you recommend? Justify your choice based on consideration of both center and variability.

p(x) 0.4 0.3 0.2 0. 0.2 0.6 0.2 0

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Referring back to Example 614 we see that both distributions of the number of flaws per panel have ... View full answer

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