Question: Figure shows a proton (p) on the central axis through a disk with a uniform charge density due to excess electrons. Three of those electrons

Figure shows a proton (p) on the central axis through a disk with a uniform charge density due to excess electrons. Three of those electrons are shown: electron ec, at the disk center and electrons es at opposite sides of the disk, at radius R from the center. The proton is initially at distance z = R = 2.00 cm from the disk. At that location, what are the magnitudes of

(a) The electric field Ec, due to electron ec, and

(b) The net electric field Es,net due to electrons es? The proton is then moved to z = R/10.0. What then are the magnitudes of

(c) Ec and

(d) Es,net at the proton's location?

(e) From (a) and (c) we see that as the proton gets nearer to the disk, the magnitude of Ec increases. Why does the magnitude of Es,net, decrease, as we see from (b) and(d)?

R- -R-

R- -R-

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a The electron ee is a distance r z 0020 m away Thus 89910 NmC16010 C 0020 m Ec E snet b The ... View full answer

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