Figure shows a rectangular loop of wire, 0.30 m wide and 1.50 m long, in the vertical plane and perpendicular to a uniform magnetic field B = 0.40 T, directed inward as shown. The portion of the loop not in the magnetic field is 0.10 m long. The resistance of the loop is 0.20 ? and its mass is 0.50 kg. The loop is released from rest at t = 0.

(a) What is the magnitude and direction of the induced current when the loop has a downward velocity v?

(b) What is the force that acts on the loop as a result of this current? (c) What is the net force acting on the loop?

(d) Write the equation of motion of the loop.

(e) Obtain an expression for the velocity of the loop as a function of time.

(f) Integrate the expression obtained in part (e) to find the displacement y as a function of time.

(g) From the result obtained in part (f) Find t for y = 1.40 m, i.e., the time when the loop leaves the region of magnetic field.

(h) Find the velocity of the loop at that instant.

(i) What would be the velocity of the loop after it has dropped 1.40 m if B = 0?

x x x x x X x X