Question: Find the error in the following proof that 0 = 1, In (1/t) dt, set u = 1/t and dv = dt. Then du

Find the error in the following "proof" that 0 = 1, In ∫ (1/t) dt, set u = 1/t and dv = dt. Then du = -t-2 dt and uv = 1. Integration by parts gives
∫ (1/t)dt = 1 - ∫ (-1/t)dt or 0 = 1

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