AP CALC MIDTERM

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Calculus - Geometry

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kipkogeibrxwzp Created by 6 mon ago

Cards in this deck(58)
6
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(3x-3)/√(2x-3)
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1 and 3
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1/2a^2
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7b -a
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-3
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2/3 < x < 2
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e^t/2 +c
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-6x^2 sin(x^3)cos(x^3)
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6
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13
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y=-2(x- (pi/4))
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E) the graph goes from positive to negative on the negative y side and at 0 switches from positive to negative again
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(1/2, 1/8)
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(-infinity, 2)
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2.6
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lim of x->a f(x) = 2
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-25/27
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sin(3) + sin(5) /8
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nonexistent
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-1
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0 ∫1 √x dx
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e^2x (2x-1) / 2x^2
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-1.89
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4.3
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1 and 2
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0.168
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57.60
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-8
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0.91
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1/4
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1.48
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12
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1 and 3 only
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-5
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2.5
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1/2
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0 and 2 only
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3
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3
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-e^-x cost(e^-x)
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f''(1) < f'(1) < f(1)
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Y= x+1
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-1 and 0
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-3
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0,infinity
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21
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8
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-0.391
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-(0.1)C
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f
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three
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160
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y=x-0.122
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f has a relative minimum at x=-2 and a relative maximum at x=2
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a is decreasing only when b>h
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1 2 and 3
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1.120
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