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MATH 308 tst 1

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Calculus - Geometry

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user_striner Created by 6 mon ago

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ordinary defferential equation
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Partial Differential Equation
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Goes off of the highest y prime value
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there is modification to the Y values I.E. sin(dy/dt) or (dy/dt)^2
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a solution that contains constants in the form of C's
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must satisfy (du/dt) = au, integrating factor is u(t)=e^at gen sol: u(t)=e^int(P(t)st) for eq (dy/dt)+P(t)Y=g(t)
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a(dy^2/Dt^2)+P(t)(dy/dt)+cy=0 use a P(t) and c to construct ar^2+br+c=0 solve for r and if two real r's plug into y=C1e^r1t+C2e^r2t
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