For H2(g) + Br2(g) 2HBr(g) K = 72 10-4 at 1362K and H is positive.

Question:

For H2(g) + Br2(g) ⇌ 2HBr(g) K = 72 × 10-4 at 1362K and ∆H° is positive. A vessel is charged with 48.0 PA HBr,1370 PaH2, and 3310 Pa Br2 at 1362 K.
(a) Will the reaction proceed to the left or the right to reach equilibrium?
(b) Calculate the pressure (in pascals) of each species in the vessel at equilibrium.
(c) If the mixture at equilibrium is compressed to half of its original volume, will the reaction proceed to the left or the right to reestablish equilibrium?