For parts (a) and (b) of this problem, use the following standard reduction potentials, free energies, and nonequilibrium concentrations of reactants and products:
ATP = 3.10 mMPi = 5. mM 5.90ADP = 220 = μM
Glucose = 5.10 mMPyruvate = 62.0 μM
NAD+ = 350 μMNADH = 15.o μMCO 2 = 15.o torr

a. Consider the last two steps in the alcoholic fermentation of glucose by brewer's yeast:

Calculate the non equilibrium concentration of ethanol in yeast cells, if ˆ†G = - 38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above
b. Consider the degradation of glucose to pyruvate by the glycolytic pathway:

Calculate ˆ†G for this reaction at pH = 7.4 and 37 °C.

Transcribed Image Text:

half reaction NAD+H2eNADH 2Pvruvate + 6H+ + 4e-_→ glucose E (V) -U.315 -0,590 pyruvate NADH2H ethanol NAD CO AG64.4 kJ/mol ATP + H2O → ADP + P, + H+ AG-32.2 kJ/mol pyruvate t NADH 2Hethano NAD + CO2 glucose + 2ADP + 2P, + 2NAD"- > 2 pyruvate 2 pyruvate 2ATP 2ATP