For the Adams-Bashforth and Adams-Moulton methods of order four, a. Show that if f = 0, then
Question:
a. Show that if f = 0, then
F(ti , h,wi+1, . . . ,wi+1ˆ’m) = 0.
b. Show that if f satisfies a Lipschitz condition with constant L, then a constant C exists with
Transcribed Image Text:
|F(ti, h, wi+1..... Wi+l-m) – F(li, h, vi+1..... Vi+l-m)|
|F(ti, h, wi+1..... Wi+l-m) – F(li, h, vi+1..... Vi+l-m)|
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